Question

Find m 11 years ago

Answer 1

Remember the "Law Of Cosines"
you can start with:
\[A ^{2} = B ^{2} + C ^{2} - 2bc COS (A)\]
Then solve for cos(A) or go right to:
\[\cos(A) = B ^{2} + C ^{2} - A ^{2} \over 2bc\]
calculator exercise now
(replace a by 34, b by 28, c by 15)
= 101.1 then round it down and your answer is triangle 28, 15, 34 angles

Hope this helps you, have a nice day.
Tag me on anymore you need help with! :)

Answer 2

wait which equation am I using ? @DatChinookGuy

Answer 3

a^2 = b^2 + c^2 - 2bc*cos(A)

Answer 4

ok so i got 1156=784+225-840 cosA

Answer 5

@DatChinookGuy

Answer 6

and then 147=-840 cosA

Answer 7

Correct!

Answer 8

Ok! and now how do i solve from there? 147-(-840)? and the cos A? @DatChinookGuy

Answer 9

63, a^2=b^2+c^2 -2bc(cos(A))
*63*

Answer 10

what is 63? @DatChinookGuy