Question

WILL FAN AND MEDAL!!!!!! Which equations are equations for the line shown?

Choose all answers that are correct

Answer 1

@dan815

Answer 2

@e.mccormick

Answer 3

@sammixboo

Answer 4

@sleepyjess

Answer 5

anybody?

Answer 6

@zepdrix

Answer 7

:P

Answer 8

@Ashleyisakitty

Answer 9

Can someone answer them it's only 2 questions...I really need help

Answer 10

@triciaal

Answer 11

....

Answer 12

@dan815 @Ashleyisakitty can you guys help me?

Answer 13

@sammixboo ???

Answer 14

anyone?

Answer 15

@Mehek14

Answer 16

@Austin6i6

Answer 17

hey how can i help u

Answer 18

can you help me answer the questions above?

Answer 19

the attachments

Answer 20

sure whats the question

Answer 21

they're above :)

Answer 22

anybody at all? these are the last 2 questions I have to answer in order to pass

Answer 23

the graph one is a

Answer 24

are you sure?

Answer 25

it's supposed to be more then one answer

Answer 26

the second one u posted not the first one

Answer 27

wait no sorry its D

Answer 28

sorry

Answer 29

give me a min ill explain it to u

Answer 30

ok...

Answer 31

look at where the line crosses the y axis

Answer 32

mhm

Answer 33

first one....find the slope by using the slope formula and the two sets of points on the line
slope(m) = (y2 - y1) / (x2 - x1)
(3,4)...x1 = 3 and y1 = 4
(-3,1)...x2 = -3 and y2 = 1
now we sub
slope(m) = (1 - 4) / (-3-3)
slope(m) = -3/-6
slope(m) = 1/2

now use y - y1 = m(x - x1)
slope(m) = 1/2
(3,4)..x1 = 3 and y1 = 4
now we sub
y - 4 = 1/2(x - 3) <=== here is one

same thing using other points
y - y1 = m(x - x1)
slope(m) = 1/2
(-3,1)....x1 = -3 and y1 = 1
now we sub
y - 1 = 1/2(x - (-3)
y - 1 = 1/2(x + 3) <=== here is another one

Answer 34

cool what about the second one?

Answer 35

ok...lets see what I can do with it...give me a sec

Answer 36

slope(m) = (y2 - y1) / (x2 - x1)
(0,1)...x1 = 0 and y1 = 1
(2,-2)...x2 = 2 and y2 = -2
now we sub
slope(m) = (-2-1) / (2-0)
slope(m) = -3/2

now use y - y1 = m(x - x1)
slope(m) = -3/2
(0,1)...x1 = 0 and y1 = 1
y - 1 = -3/2(x - 0)

y - y1 = m(x - x1)
(2,-2)...x1 = 2 and y1 = -2
y - (-2) = -3/2(x - 2)
y + 2 = -3/2(x - 2)

hmmm...not getting your answer choices
let me try something
y + 2 = -3/2(x - 2)
y + 2 = -3/2x + 3
y = -3/2x + 3 - 2
y = -3/2x + 1

y - 4 = -3/2(x + 2)
y - 4 = -3/2x - 3
y = -3/2x - 3 + 4
y = -3/2x + 1

ok....its gonna be y - 4 = -3/2(x + 2)

Answer 37

I see what I did...I should have used the points (-2,4) and I would have gotten to the answer a whole lot easier

Answer 38

you sure?? final answer?

Answer 39

positive

Answer 40

ok thanks I got %100

Answer 41

sweet :) I love to hear that

Answer 42

do you think you could help me with something else?