I need help I've been asking and no one is doing anything to help

Question

anonymous · Answer

@Niguyver

anonymous · Answer

help with what??

misty1212 · Answer

HI!!

misty1212 · Answer

what do you need help with?

texaschic101 · Answer

now that you have everyone's attention...what is your question ?

texaschic101 · Answer

ok....well....this is why nobody is helping

anonymous · Answer

At the city museum, child admission is 



$

6.60
 and adult admission is 



$

9.70
. On Saturday, twice as many adult tickets as child tickets were sold, for a total sales of 



$

520.00
. How many child tickets were sold that day?

misty1212 · Answer

lets call the number of child tickets say $x$ so the number of adult tickets sold is $2x$
childs bring in $6.60x$ and adults bring $9.70\times 2x$ set 
$$6.60x+2\times 9.70x=520.00$$ and solve for $x$

texaschic101 · Answer

twice as many adult tickets as child tickets were sold
2c = a

childs tickets are 6.60....adult tickets are 9.70...for a total of 520
6.60c + 9.70a = 520

now we will sub in 2c for a
6.60c + 9.70(2c) = 520
6.60c + 19.40c = 520
26c = 520
c = 520/26
c = 20

now sub 20 in for c in the equation 2c = a and solve for adult tickets

anonymous · Answer

so is it 26? @misty1212 @texaschic101

anonymous · Answer

@sleepyhead314

anonymous · Answer

@Nnesha

texaschic101 · Answer

no..
children tickets (c) sold was 20
adult tickets (a) sold was 40