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An ideal spring with spring constant k is cut in half. What is the spring constant of either one of the two half springs? The answer is 2k but I don't understand why.
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Since f=kx, then k=f/x. Now if you apply the same force to the half-length spring it only moves half as far. So if x is halved above, then k will double. Basically there are now half as many coils to take up the force via displacement.
But isn't the x in f=kx the distance that the spring is displaced, not the length of the spring?
In some questions you can use it as a length too..
Thanks, I get it now.
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