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I will give a medal follow and give medal to anyone who can help solve: log(5x+4)=2
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what is the base of your logarithm?
if it doesnt have a base, wouldn't the base be 10?
ok! If the base is 10, then, I apply the definition of logarithm and I can rewrite your equation as below: \[\begin{gathered} 5x + 4 = {10^2} \hfill \\ 5x = 100 - 4 \hfill \\ 5x = 96 \hfill \\ \end{gathered} \] what is x?
19.2
that's right!
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If the base is 2, then, again applying the definition of logarithm, we have: \[\begin{gathered} 5x + 4 = {2^2} \hfill \\ 5x = 4 - 4 \hfill \\ 5x = 0 \hfill \\ x = 0 \hfill \\ \end{gathered} \]
but if there is no base shown, would the base automatically be 10?
yes! I think so!
Ok thank you :)
thank you! :)
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