Find the surface area of the regular pyramid shown to the nearest whole number.
A.862 m^2
B. 540 m^2
C. 1,125 m^2
D. 647 m^2
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OpenStudy (anonymous):
OpenStudy (acxbox22):
find the area of the base and the area of the triangles and add them up
OpenStudy (anonymous):
How do I do that? Base times height, right?
OpenStudy (acxbox22):
nope since it a hexagon you use the formula
(1/2)(perimeter)(apothem) for area
OpenStudy (anonymous):
Okay, I'm confused.
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OpenStudy (acxbox22):
it is the formula for the area for all regular polygons
OpenStudy (acxbox22):
do you know what the apothem is?
OpenStudy (anonymous):
That's what confused me.
OpenStudy (acxbox22):
|dw:1430697363846:dw|
OpenStudy (jdoe0001):
\(\textit{area of a regular polygon}=\cfrac{1}{2}rns\\\quad \\
\begin{cases}
r=\textit{apothem, or distance from a side to the center}\\
n=\textit{number of sides}\\
s=\textit{length of each side}
\end{cases}\)
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OpenStudy (jdoe0001):
|dw:1430698250293:dw|
OpenStudy (anonymous):
Thanks. :)
OpenStudy (jdoe0001):
then as acxbox22 said
find the triangles area, all 6 of them
sum them all up, hexagonal base and triangles