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Mathematics 18 Online
OpenStudy (anonymous):

Find the surface area of the regular pyramid shown to the nearest whole number. A.862 m^2 B. 540 m^2 C. 1,125 m^2 D. 647 m^2

OpenStudy (anonymous):

OpenStudy (acxbox22):

find the area of the base and the area of the triangles and add them up

OpenStudy (anonymous):

How do I do that? Base times height, right?

OpenStudy (acxbox22):

nope since it a hexagon you use the formula (1/2)(perimeter)(apothem) for area

OpenStudy (anonymous):

Okay, I'm confused.

OpenStudy (acxbox22):

it is the formula for the area for all regular polygons

OpenStudy (acxbox22):

do you know what the apothem is?

OpenStudy (anonymous):

That's what confused me.

OpenStudy (acxbox22):

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OpenStudy (jdoe0001):

\(\textit{area of a regular polygon}=\cfrac{1}{2}rns\\\quad \\ \begin{cases} r=\textit{apothem, or distance from a side to the center}\\ n=\textit{number of sides}\\ s=\textit{length of each side} \end{cases}\)

OpenStudy (jdoe0001):

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OpenStudy (anonymous):

Thanks. :)

OpenStudy (jdoe0001):

then as acxbox22 said find the triangles area, all 6 of them sum them all up, hexagonal base and triangles

OpenStudy (anonymous):

So the answer is 540 m^2?

OpenStudy (anonymous):

@jdoe0001

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