Question

Integral substitution? Not getting the right answer?

Answer 1

\[\int\limits_{}^{} \frac{ \sin 2x }{ 1+\cos^2x } dx\]

Answer 2

When I am doing it, I'm letting \[u=1+\cos^2x\]

Answer 3

and what are you getting stuck on?

Answer 4

I'm getting \[\frac{ du }{ dx }= -2sinxcosx\] I don't think that will help me find the integral

Answer 5

it will if you recall your trig identities ....

what is another way to write sin(2x)?

Answer 6

2sinxcosx! Oh that makes more sense

Answer 7

:) you should have the rest of it then

Answer 8

Yup I do thanks!