Question

In need of help. Will fan and medal.

Answer 1

Choose a number of items to put on the reactant side and put the rest on the products side.
For each round, half of the items that were on the reactant (R) side of the paper from the last round should be moved to the product side. One-fourth of the items that were on the product (P) side of the paper from the last round should be moved to the reactant side. (If you end up with a decimal for the number to exchange, round up.)
At the end of each round, count the number of items on each side of the paper and keep track of the numbers in a data table.
Follow the instructions in Step 2 for a total of 10 rounds.
At the end of 10 rounds, calculate the ratio (ratio = P/R ) of products to reactants.

Answer 2

@TuringTest @dan815 @Abhisar @nincompoop @Preetha @amistre64 @ganeshie8 @iGreen @aaronq @paki @iambatman @confluxepic

Answer 3

@Luigi0210 @sammixboo @undeadknight26 @johnweldon1993 @EclipsedStar @triciaal @Michele_Laino @mathmate @shifuyanli @KyanTheDoodle @Mimi_x3 @Jamierox4ev3r @chosenmatt @Haseeb96 @JoannaBlackwelder @TheAsker2002 @justuu @Jaynator495

Answer 4

#Mass-Tagging

Answer 5

Well, no one wants to take a look at any of the questions I post. I have to result to tagging.

Answer 6

I've viewed a different version of this using 40 items which was the last question to this.
There were different results ending with 14/24 and 16/26, 13/27, I already have my answer to that, now I need to create my own version of it.

I wanted to start with 120 but the first time around wasn't so well. I'd actually appreciate help from someone.

Answer 7

Can you show me what you did?

Answer 8

@alanate ??

Answer 9

@alanate, do you want help, or do you want the answer?

Answer 10

Sorry, I've been working on other things. I'd like the answer if you wouldn't mind? I've worked on it long enough, I'd like to just get it over with.
Could you work with a start of 120 like I wanted to do? I think it'd be easier because it's 3 times as much as 40 which I already had.

Answer 11

Here's some hint.
If you start with R=120, P=0, then
R->P = 120/2=60, and
P->R = 0/4 = 0
Thus the new value of R=120-60+0=60
new value of P=0+60-0=60
or
R=60, P=60 at the beginning of round 2.
Continue this way until you get to round 10 (but it steadies at round 4).

Answer 12

I already started with
120 - 0
60 - 60
45 - 75

Answer 13

Pray continue!

Answer 14

what I didn't get is how to continue after that. It didn't seem right.

120 - 0
60 - 60
45 - 75
and then I ended up with

42 - 78
or 41
or 40
and 72, 71, and 73

Answer 15

No, the remainder did not look right.
Let start at 45,75.
-> 45/2=22.5
<- 75/4=18.75
P=45-22.5+18.75=41.25
R=75-18.75+22.5=75+3.75=78.75
Round up.
P=42, R=79
(doesn't add up to 120 because of rounding up)

Answer 16

@alanate

Answer 17

so 120 - 0
60 - 60
45 - 75
42 - 79

alright, I've got the pattern.

Answer 18

thanks for responding

Answer 19

You'll need to continue to finish the problem.
My answer at the tenth iteration has P=2R.

Answer 20

I got a repeat on 41 - 81
ratio = 81/41

Answer 21

I have 41/82.
Probably rounding up made the difference.
If I had normal rounding, I would have got 40/80, the expected numbers (ratio 1:2 and add up to 120 (law of conservation of matter).