If Water is poured into a tank in the shape of a right circular cone, standing on its
vertex, and the height of the cone is 40 feet and its radius is 8 feet, and the water level in
the tank is increasing at a constant rate of 2 feet per second, how fast (in ft/sec) is the water being poured into the tank at the instant the
depth of the water is 10 feet?

Question

If Water is poured into a tank in the shape of a right circular cone, standing on its
vertex, and the height of the cone is 40 feet and its radius is 8 feet, and the water level in
the tank is increasing at a constant rate of 2 feet per second,  how fast (in ft/sec) is the water being poured into the tank at the instant the
depth of the water is 10 feet?

daniel14 · Answer

hold on

anonymous · Answer

Volume of a cone is pir^2h/3

daniel14 · Answer

@Compassionate  @e.mccormick @EclipsedStar @shifuyanli  @TheSmartOne

anonymous · Answer

what does that accomplishing? im new here

daniel14 · Answer

oh im calling people that know math better than me... it basically calls the professors here

anonymous · Answer

ok thx

daniel14 · Answer

or someone that simply enjoys math

theweeknd16 · Answer

Does this help at all ? https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&cad=rja&uact=8&ved=0CB4QFjAA&url=https%3A%2F%2Fanswers.yahoo.com%2Fquestion%2Findex%3Fqid%3D20090111142624AAaDjN5&ei=qhBIVcWkDc2ryASr_oGIDw&usg=AFQjCNEUmwRPfyTlGz2Jr9FtWKd-U57llw

anonymous · Answer

yes that's the exact same problem lol thx

theweeknd16 · Answer

Yup.