What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)?

I am doing a review I know the equation is (h-k)^2+(y-k)^2=r^2 However, I forgot how to plug in the coordinates. Can anyone help me out please? I appreciate it.

Question

What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)?

I am doing a review I know the equation is (h-k)^2+(y-k)^2=r^2 However, I forgot how to plug in the coordinates. Can anyone help me out please? I appreciate it.

exoticinspirit · Answer

@dan815

exoticinspirit · Answer

@amistre64

amistre64 · Answer

your 'knowing' is a little off

amistre64 · Answer

for some center (h,k)  and radius r ....

(x-h)^2+(y-k)^2=r^2

amistre64 · Answer

the radius of a circle is the distance from the center to a point in the edge ....

how do we find the distance between 2 points?

amistre64 · Answer

well, we just use the circle equation really

a point (a,b) on a circle satisfies

(a-h)^2 + (b-k)^2 = r^2

exoticinspirit · Answer

Thanks I already found the answer though