Question

Simplifying:
tan(theta) + cos (-theta) + tan(-theta)
how do I get rid of negative thetas?

Answer 1

tan(Θ)+cos(−Θ)+tan(−Θ)

(sinΘ/cosΘ)+cos(−Θ)+(sin/cos)(−Θ)

Answer 2

Hey Nini :)

Cosine is an even function meaning, \(\Large\rm \cos(-\theta)=\cos(\theta)\)
Sine and Tangent are odd functions therefore, \(\Large\rm \tan(-\theta)=-\tan(\theta)\)
and \(\Large\rm \sin(-\theta)=-\sin(\theta)\)

Answer 3

Do you understand how to apply these properties to your problem?
No need to convert to sines and cosines ^^

Answer 4

Hello:) haha you made my night by saying hi, thank you!

Um, yes I think so.
The original equation would be:
\[\tan(\Theta) +\cos(\Theta) - \tan(\Theta)\]
which would come out to: cos(Theta) ?

Answer 5

Yay good job \c:/

Answer 6

yayay!