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Write the equation of the line with a slope of -5 and a y-intercept of (0,3)
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Put it in point-slope form first. \(\sf y - y_1 = m(x - x_1)\) Where \(\sf y_1\) is the y-value of the point, \(\sf x_1\) is the x-value of the point, and \(\sf m\) is the slope.
so 3-0=-5(3-0)
No, we don't do anything to 'x' or 'y'
so
(0, 3) x1 y1
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m = -5
You got the slope right. \(\sf y - y_1 = -5(x - x_1)\)
okay. so y-3=-5(x-0)
Yep!
and that is the equation?
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Yes, do you have choices? It might want it in slope-intercept form.
nah. I don't think it does because it doesn't say anything about slope intercept
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