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Mathematics 19 Online
OpenStudy (anonymous):

Mrs. Jones buys two toys for her son. The probability that the first toy is defective is 1/3, and the probability that the second toy is defective given that the first toy is defective is 1/5. What is the probability that both toys are defective? 1/15 1/4 1/8 3/5

OpenStudy (anonymous):

@jennyrlz

OpenStudy (jennyrlz):

heyo :)

OpenStudy (jennyrlz):

ok so i will try to go about this problem the same way

OpenStudy (jennyrlz):

but you can do it another way aswell that i will explain after

OpenStudy (anonymous):

ok

OpenStudy (jennyrlz):

so the first way is to do it as the last problem

OpenStudy (jennyrlz):

turn the fractions into decimals

OpenStudy (jennyrlz):

1/3=.33333333333 1/5=.2

OpenStudy (jennyrlz):

then multiply both to get .066666666

OpenStudy (jennyrlz):

the you can simply divide the ansewr choices for example 1 divided by 15= .06666

OpenStudy (jennyrlz):

so that is the answer :)

OpenStudy (jennyrlz):

you redy for the easy way?

OpenStudy (jennyrlz):

when multiplying fractions they dont need a common denominator

OpenStudy (jennyrlz):

so 1/3 x 1/5

OpenStudy (jennyrlz):

1x1 --- 3x15

OpenStudy (jennyrlz):

1/15

OpenStudy (jennyrlz):

same answer :)

OpenStudy (anonymous):

right thanks

OpenStudy (jennyrlz):

dont forget to medal :)

OpenStudy (anonymous):

thanks alot

OpenStudy (jennyrlz):

no problem, as long as i have ability to do it, will help :)

OpenStudy (anonymous):

cool

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