Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Jason is a used-car salesman who sells domestic and foreign cars. He earns $7,000 for each domestic car sold and loses $3,500 for each foreign car sold. Due to certain business commitments, Jason has to sell at least 10 foreign cars each month. He needs to make at least $17,000 each month to cover his expenses. Which graph shows the number of cars he has to sell each month to at least cover his expenses?

OpenStudy (anonymous):

OpenStudy (amistre64):

what are your thoughts?

OpenStudy (anonymous):

Leaning towards C

OpenStudy (amistre64):

me too at a first glance, but can you defend your position?

OpenStudy (amistre64):

spose he sells, 11 fcars, whats his total loss that has to be made up?

OpenStudy (anonymous):

38,500, then hed have to sell 6 american cars to come up positive

OpenStudy (amistre64):

11(3500) + 17000 = 55500 55500/7000 = about 8 ----------------------- so the point (8,11) is a profit point that should be on neither boundary line

OpenStudy (anonymous):

Which is c

OpenStudy (amistre64):

yeah, or we can do it simpler or pick a point thats clearly on a side ... (15,15) 15(7000) - 15(3500) > 17000 if its good, we pick that side

OpenStudy (amistre64):

52500 > 17000 so (15,15) is the winning shade :) C is fine

OpenStudy (anonymous):

Sweet (:

OpenStudy (amistre64):

8 and 11 were just too close for comfort to me :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!