Will fan and medal if you help!!!
How many "red cards" are there in a standard deck of cards ?
52
http://www.2classnotes.com/images/10/mathematics/probability/playing_cards.gif
Total cards are 52, how many of them are "red" ?
26
Good, how many of those "red cards" are "Aces" ?
2
Very good, so the probability of drawing a "red Ace" first time is : \[\frac{2}{52}\] After that drawing an Ace is \[\frac{3}{51}\] Multiply them to get the total probability \[\frac{2}{52}\times \frac{3}{51}\] simplify
so 1/442
Yes drag the first box and place it before 1/442
i did
Lets look at second box
look at the deck of cards again how many of them are either "3" or "5" ?
3 = 2 5= 2
count them again
count both red and black
ok so 3=4 5=4
So, the cards in favor are 8 therefore the probability of drawing "3" or "5" is \[\frac{8}{52}\] Similarly, after putting the drawn card back in the deck, the probability of drawing "4" or "6" is \[\frac{8}{52}\] Multiply them to get the total probability
so 4/169
Yep!
see if you can try the problem in 3rd box
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