What is the length of stack EC with bar on top in the rectangular prism? Round to the nearest tenth of a centimeter.
A.7.5 cm
B.9.4 cm
C.12.6 cm
D.15.3 cm
http://static.k12.com/calms_media/media/1579000_1579500/1579368/1/d5792698202fbbf409095d22a45a964cdf2a7154/MS_IMC-150126-130907.jpg
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OpenStudy (vcabral1134):
Will fan and medal!
OpenStudy (vcabral1134):
@Preetha
OpenStudy (vcabral1134):
@Michele_Laino
OpenStudy (vcabral1134):
@confluxepic
OpenStudy (vcabral1134):
Anybody??
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OpenStudy (anonymous):
the aswer is 15.3 i am 100 percent sure
OpenStudy (vcabral1134):
Thank you but can you explain so next time I have a question like this I can do it on my own @sarimari
OpenStudy (anonymous):
okay i will try cause i am not very good at explaning math bu here it goes
OpenStudy (michele_laino):
hint:
you have to apply the Theorem of Pitagora twice.
From your picture, we have:
\[E{C^2} = E{G^2} + G{C^2}\]
or:
\[EC = \sqrt {E{G^2} + G{C^2}} \]
OpenStudy (michele_laino):
nevertheless we aren't able to compute EC, since we don't know what is EG. So we apply again the Theorem of Pitagora, and we can write:
\[\Large E{G^2} = E{F^2} + F{G^2} = {8^2} + {5^2} = 64 + 25 = ...?\]
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OpenStudy (michele_laino):
so what is EG^2=...?
OpenStudy (vcabral1134):
89/
OpenStudy (michele_laino):
ok! Now we have to substitute that value into our first formula, so we get:
\[\Large EC = \sqrt {E{G^2} + G{C^2}} = \sqrt {89 + {{12}^2}} = \sqrt {89 + 144} = ...?\]
OpenStudy (vcabral1134):
15.2
OpenStudy (michele_laino):
better is 15.3, since we got 15.26...
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