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Mathematics 16 Online
OpenStudy (vcabral1134):

What is the length of stack EC with bar on top in the rectangular prism? Round to the nearest tenth of a centimeter. A.7.5 cm B.9.4 cm C.12.6 cm D.15.3 cm http://static.k12.com/calms_media/media/1579000_1579500/1579368/1/d5792698202fbbf409095d22a45a964cdf2a7154/MS_IMC-150126-130907.jpg

OpenStudy (vcabral1134):

Will fan and medal!

OpenStudy (vcabral1134):

@Preetha

OpenStudy (vcabral1134):

@Michele_Laino

OpenStudy (vcabral1134):

@confluxepic

OpenStudy (vcabral1134):

Anybody??

OpenStudy (anonymous):

the aswer is 15.3 i am 100 percent sure

OpenStudy (vcabral1134):

Thank you but can you explain so next time I have a question like this I can do it on my own @sarimari

OpenStudy (anonymous):

okay i will try cause i am not very good at explaning math bu here it goes

OpenStudy (michele_laino):

hint: you have to apply the Theorem of Pitagora twice. From your picture, we have: \[E{C^2} = E{G^2} + G{C^2}\] or: \[EC = \sqrt {E{G^2} + G{C^2}} \]

OpenStudy (michele_laino):

nevertheless we aren't able to compute EC, since we don't know what is EG. So we apply again the Theorem of Pitagora, and we can write: \[\Large E{G^2} = E{F^2} + F{G^2} = {8^2} + {5^2} = 64 + 25 = ...?\]

OpenStudy (michele_laino):

so what is EG^2=...?

OpenStudy (vcabral1134):

89/

OpenStudy (michele_laino):

ok! Now we have to substitute that value into our first formula, so we get: \[\Large EC = \sqrt {E{G^2} + G{C^2}} = \sqrt {89 + {{12}^2}} = \sqrt {89 + 144} = ...?\]

OpenStudy (vcabral1134):

15.2

OpenStudy (michele_laino):

better is 15.3, since we got 15.26...

OpenStudy (vcabral1134):

oh

OpenStudy (vcabral1134):

Thank you for explaining!

OpenStudy (michele_laino):

Thank you! @VCabral1134 @sarimari

OpenStudy (anonymous):

np anytime

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