What is the limit of f(x) =

as x approaches infinity?

Question

What is the limit of f(x) = 

as x approaches infinity?

geerky42 · Answer

$$ -\frac{ 4x^2-6 }{ 4x^2-1 } = -\frac{ 4x^2-1 -5}{ 4x^2-1 } = -\frac{ 4x^2-1 }{ 4x^2-1 } +\frac{ 5 }{ 4x^2-1 } = -1+\frac{ 5}{ 4x^2-1 }$$

geerky42 · Answer

OR you can apply L'Hopital's Rule few times.

geerky42 · Answer

Hmm, -1 isn't in options?

geerky42 · Answer

Oh, so there you go.

geerky42 · Answer

Do you understand what I did here, right?

geerky42 · Answer

No, it is really -1.

Maybe report this problem (if you are online)?

geerky42 · Answer

anonymous · Answer

yea I put it in wolfram too I know

anonymous · Answer

geerky42 · Answer

Yeah something is wrong with question. Just report it or notify teacher, or whatever

anonymous · Answer

:)