Question

What is the limit of f(x) =

as x approaches infinity?

Answer 1

\[ -\frac{ 4x^2-6 }{ 4x^2-1 } = -\frac{ 4x^2-1 -5}{ 4x^2-1 } = -\frac{ 4x^2-1 }{ 4x^2-1 } +\frac{ 5 }{ 4x^2-1 } = -1+\frac{ 5}{ 4x^2-1 }\]

Answer 2

OR you can apply L'Hopital's Rule few times.

Answer 3

Hmm, -1 isn't in options?

Answer 4

Oh, so there you go.

Answer 5

Do you understand what I did here, right?

Answer 6

No, it is really -1.

Maybe report this problem (if you are online)?

Answer 7

http://www.wolframalpha.com/input/?t=crmtb01&f=ob&i=lim%20as%20x%20to%20infinity%20-(4x%5E2-6)%2F(4x%5E2-1)

Answer 8

yea I put it in wolfram too I know

Answer 9

https://www.symbolab.com/solver/limit-calculator/%5Clim_%7Bx%5Cto%20%5Cinfty%7D%5Cleft(-%5Cfrac%7B4x%5E%7B2%7D-6%7D%7B4x%5E%7B2%7D-1%7D%5Cright)/?origin=button

Answer 10

Yeah something is wrong with question. Just report it or notify teacher, or whatever

Answer 11

:)