John stands on the topmost tier of seats in a baseball stadium, and throws a ball out onto the field with a vertical upward velocity of 60 ft/sec. The ball is 50 feet above the ground at the moment he releases the ball. When does the ball land?
The height function h(t) is given by h(t) = \[h(t) =1/2\gt^2 + v _{0}t + k\] Where g is 32 ft/sec^2, \[v _{0}\] = 60 ft/sec and k = 50 ft
@Loser66
what does 1/2 >^2 mean?
oh, that's supposed to say -1/2gt^2
so, you are good
When I tried to do it, I got h(t) = -16t^2 + 60t + 50 but I got the problem marked wrong
What's you choices
It's an open ended problem
fight back. You are correct
What was the answer you got?
I think my answer was wrong which is what the problem was
The same as your. And I check on the other site. They agree with us. http://stufiles.sanjac.edu/Placement_Testing_Review/Math/Solving_Quadratic_Equations/Solving_Quadratic_Equations4.html
If you think you are correct or you are not sure about why it is wrong, ask your prof to get the credit back.
Hmm. I will, I'll do that today. Thank you!
ok, print the paper on that site and show it to him if needed
Good point
Can you guys fan me @LifeIsADangerousGame @Loser66 and medal me
You did nothing to be fan or medal
Why?
I just wanted you guys to medal and fan me. I want to be up there with you guys, I'm still helping everyone out, look at the questions I answered.
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