Consider this system of linear equations:

22x − y = -23 (equation 1)

11x + 12y = 1 (equation 2)

To find the value of x, you need to substitute in equation 2.
The value of x is .

Question

Consider this system of linear equations:

22x − y = -23           (equation 1)

11x + 12y = 1          (equation 2)

To find the value of x, you need to substitute  in equation 2.
The value of x is .

kidrah69 · Answer

ok well fist you need to get X equals or a y equals equation

kidrah69 · Answer

Do you know how to do that?

anonymous · Answer

no

kidrah69 · Answer

Hint: since the first one has a varible only and no number nxt to it it will be easier

kidrah69 · Answer

$$-y=-22x-23$$
here i did that step now just divide everything by -1 to get a positive Y value

anonymous · Answer

how would we get a positive out of this

kidrah69 · Answer

$$\frac{ −y=−22x−23 }{ -1=-1-1~~ }$$

kidrah69 · Answer

A negative times a negative is a positive same works for division

anonymous · Answer

wouldn't it be 22x and 23 because -1 can go into -22x 22 time right?

kidrah69 · Answer

nope the equation stays the same the signs flip :P

anonymous · Answer

i dont understand

kidrah69 · Answer

$$y=22x+23$$

kidrah69 · Answer

thats all

anonymous · Answer

okay but what about the value of x?

kidrah69 · Answer

Well we have out equation ONE so now substitute!
$$11x + 12(22x+23) = 1        $$
this will get you the X value
Solve.

anonymous · Answer

wouldn't it be 1

kidrah69 · Answer

now 1 but -1

anonymous · Answer

oh so -1 is my answer

kidrah69 · Answer

now all you do is plug the X value in equation 1 
$$y=22(-1)+23$$
yes the x=-1