Solve sin(x) - √(1 - 3sin²(x)) = 0 given that 0° ≤ x ≤ 360°.

I did
sin(x) = √(1 - 3sin²(x))
sin²(x) = 1 - 3sin²(x)
sin²(x) + 3sin²(x) - 1
4sin²(x) - 1
(2sin(x) + 1)(2sin(x) - 1)
sin(x) = -1/2 and 1/2
x = 30°, 150°, 210°
But when I graph it I get 30°, 150°, 210°, and 330°

Question

Solve sin(x) - √(1 - 3sin²(x)) = 0 given that 0° ≤ x ≤ 360°.

I did 
sin(x) = √(1 - 3sin²(x))
sin²(x) = 1 - 3sin²(x)
sin²(x) + 3sin²(x) - 1
4sin²(x) - 1
(2sin(x) + 1)(2sin(x) - 1)
sin(x) = -1/2 and 1/2
x = 30°, 150°, 210°
But when I graph it I get 30°, 150°, 210°, and 330°

anonymous · Answer

I dont know what the right answer is :(

nnesha · Answer

|dw:1431052107054:dw|
cast rule

nnesha · Answer

|dw:1431052131976:dw|