Mathematics
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OpenStudy (anonymous):
HELP PLEASE !!! <3
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OpenStudy (anonymous):
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
ok that was wrong sorry
OpenStudy (anonymous):
what was wrong?
OpenStudy (anonymous):
for \(-4\) and \(3\) use the top rule so
\[h(-4)=\frac{1}{2}\times (-4)-1\]
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OpenStudy (anonymous):
\[h(3)=\frac{1}{2}\times 3-1\]
OpenStudy (anonymous):
and you are told \(h(-1)=4\)
OpenStudy (anonymous):
first one is 2, second one is 1.5?
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
@dan815
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OpenStudy (dan815):
tope try again
OpenStudy (dan815):
nope*
OpenStudy (anonymous):
i dont really understand it, can you explain what to do?
OpenStudy (anonymous):
did you compute?
OpenStudy (anonymous):
yes, ^^
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OpenStudy (anonymous):
\[\frac{1}{2}\times (-4)=1=-2-1=-3\]
OpenStudy (anonymous):
-2=1=-3=-3?
OpenStudy (anonymous):
oops i meant
\[\frac{1}{2}\times (-4)-1=-2-1=-3\]
OpenStudy (anonymous):
lets say it in inglish
one half of minus four is minus two
minus two minus one is minus three
OpenStudy (anonymous):
-3=-3=-3?
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OpenStudy (dan815):
lol megan xD
OpenStudy (anonymous):
lol am i retarded?
OpenStudy (dan815):
lmaaooo
OpenStudy (dan815):
nope :)
OpenStudy (anonymous):
lol im not understanding.
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OpenStudy (dan815):
okay so when x is not -1 you stick it into the other equality
h(x)=x/2-1 when x is not -1
OpenStudy (dan815):
h(-4)=-4/2 -1 = -2-1 =-3
OpenStudy (dan815):
h(-1)=4 that is given
OpenStudy (anonymous):
so the answer for h(-1)=4?
OpenStudy (dan815):
h(3)=3/2-1=1.5-1=0.5=1/2
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OpenStudy (dan815):
yeaah
OpenStudy (anonymous):
ok so the other ones should be..
OpenStudy (dan815):
if x=-1 then h(x)=4
if x is not -1 then h(x)=1/2* x -1
OpenStudy (anonymous):
i dont know what youre saying tbh.
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OpenStudy (dan815):
T_T
OpenStudy (anonymous):
im sorry, can you explain a little less complicatedly? :(
OpenStudy (dan815):
okay so this is how a function works h(x) =x/2-1
it means when you pick a value for x, you replace wherever you see that x with it in the equation
OpenStudy (anonymous):
okay but the h(x) when there is a number there, what happenes to the h?
OpenStudy (anonymous):
@Mateaus Please help? :(
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OpenStudy (anonymous):
what's the issue?
OpenStudy (anonymous):
im not understanding at all of how to do this
OpenStudy (anonymous):
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