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Chemistry 17 Online
OpenStudy (anonymous):

I AM TAKING A TIMED QUIZ PLEASE HELP MISSING TWO QUESTIONS Determine which of the following is the correct equilibrium expression for the chemical reaction: N2 (g) + 3Cl2 (g) 2NCl3 (g)

OpenStudy (anonymous):

Kc = [NCl]6/([N]2[Cl]6) Kc = ([N2][Cl2]3)/[NCl3]2 Kc = ([N]2[Cl]6)/[NCl]6 Kc = [NCl3]2/([N2][Cl2]3)

OpenStudy (australopithecus):

which do you think it is

OpenStudy (australopithecus):

OpenStudy (australopithecus):

This should help

OpenStudy (anonymous):

It's the last one, am I correct??? @Australopithecus

OpenStudy (australopithecus):

It is kind of unethical for me to help you if I know you are writing a quiz even though I just did confirming answers is where I draw the line. If you think that is the correct answer than submit it.

OpenStudy (australopithecus):

then*

OpenStudy (australopithecus):

As long as you followed the formula I provided you are fine

OpenStudy (australopithecus):

also I apologize for the poor grammar not a 100% right now but I am a 100% sure that information I provided you is correct.

OpenStudy (australopithecus):

Do you have another question?

OpenStudy (anonymous):

I do yes @Australopithecus

OpenStudy (anonymous):

Let me post it

OpenStudy (anonymous):

For which of the following reactions will a decrease in pressure shift the equilibrium to the left? 2A2 (g) + B2 (g) -> 2A2B (g) 2AB (g) -> A2 (g)+ B2 (g) 2A2F3 (g) -> 4A (g) + 3F2 (g) 2B (s) + 2HA (aq) -> 2BA (aq) + H2 (g)

OpenStudy (anonymous):

I feel that the answer is B

OpenStudy (australopithecus):

When you decrease pressure molecules will not hit into each other as often and therefore not react as often.

OpenStudy (australopithecus):

Also note the more molecules you have to have collide the less chance they will collide in the right way to cause a reaction to occur

OpenStudy (australopithecus):

physically a decrease in pressure means the molecules are farther apart in space

OpenStudy (australopithecus):

actually to change this, also note the more molecules you have to have collide the less chance they will collide at all or even in the right way to cause a reaction to occur

OpenStudy (australopithecus):

Its like if you had 2 people each with a ball and you wanted them to throw both the balls so that they hit each other. Now imagine you have 3 people each with a ball and you wanted them to throw three balls so that they hit eachother. Logically you would say that the people with the three balls would have less chance of being successful at hitting them together. Now imagine the balls have a few pegs and grooves in them. It would be considered even less likely that the 3 balls would come together correctly so that the pegs fit into the grooves than the 2 balls

OpenStudy (australopithecus):

A decrease in pressure causes the people throwing the balls to be farther apart. Therefore logically the people throwing the three balls would have even less of a chance than those with two balls

OpenStudy (australopithecus):

let me know if you follow

OpenStudy (anonymous):

I follow

OpenStudy (australopithecus):

alright awesome I hope you do well :D

OpenStudy (australopithecus):

If the left side doesnt react as readily as the right side in a equilibrium chemical reaction the left side chemicals will build up If the right side doesnt react as readily as the left side in a equilibrium chemical reaction the right side chemicals will build up

OpenStudy (australopithecus):

Just putting this out there just to make sure you dont make an incorrect conclusion

OpenStudy (australopithecus):

Also a shift in equilibrium to the left means that there will be more reactants existing a shift to the right means more product will exist

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