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Mathematics 8 Online
OpenStudy (anonymous):

Help asap please! On a deadline, posting below

OpenStudy (anonymous):

The length of a box is 5 more than the width and the height is 2 less than the width. If the volume is equal to 150 cubic feet, what are the measurements for each side.

OpenStudy (anonymous):

this was my answer v = lw h w = x l = x + 5 h = x – 2 x(2 – 5)(x + 5) = 150

OpenStudy (anonymous):

but my teacher said i found the variable but didnt list the length of sides, so i need to fix that

OpenStudy (anonymous):

Yeah. You didn't complete it all the way

OpenStudy (anonymous):

ok since you know the expression, just multiply out to solve for "w" using your same w(w+5)(w-2)=150

OpenStudy (anonymous):

what do you mean? @incomplte

OpenStudy (anonymous):

Remember the question asks for the length of the sides. So we have to find, L, H, and W

OpenStudy (anonymous):

I used W as the X in your eqns. V=LWH V=(W+5)(W)(W-2), but we already know V=150. so 150=(W+5)(W)(W-2). Get it?

OpenStudy (anonymous):

so lost

OpenStudy (anonymous):

@incomplte

OpenStudy (anonymous):

oh shoot

OpenStudy (anonymous):

ok should i just use x as you did. Maybe that will make it easier to understand?

OpenStudy (anonymous):

yeah lets try that

OpenStudy (anonymous):

ok.so v = lwh w = x l = x + 5 h = x – 2. You understand up to this point?

OpenStudy (anonymous):

yeah thats how i had it written

OpenStudy (anonymous):

ok yeah, i just copied it and wanted to make sure you understood

OpenStudy (anonymous):

since we know that v=lwh we can also substitute l as (x+5), and w=x, and h=(x-2) into the equation above, and say v=(x+5)*(x)*(x-2). Do you understand this part?

OpenStudy (anonymous):

okay, where would i put that?

OpenStudy (anonymous):

with L?

OpenStudy (anonymous):

i gotta get ready for work in a couple minutes. -_-

OpenStudy (anonymous):

ok i don't think you are understanding. remember that L=(x+5), this means L and (x+5) are the same thing, so I'm just putting (x+5) into the equation in place of L, and doing the same thing with the other values

OpenStudy (anonymous):

okay i got that part

OpenStudy (anonymous):

ok so you understand v=(x+5)*(x)*(x-2)

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok cool. remember that they already told us that v=150, so we can rewrite as 150=(x+5)*(x)*(x-2). Do you understand?

OpenStudy (anonymous):

so far yes

OpenStudy (anonymous):

ok cool. so now we can multiply out since everything on the right side is in terms of x, so we can say 150=(x^3 + 3x^2 -10). got it?

OpenStudy (anonymous):

got it

OpenStudy (anonymous):

cool so now we have to solve for x. 150=(x^3 + 3x^2 -10x). can you do that?

OpenStudy (anonymous):

i really really have to go get ready now, can we continue this tomorrow? Because i miiiiiiiiight need help solving for x

OpenStudy (anonymous):

@incomplte

OpenStudy (anonymous):

@KendrickLamar2014

OpenStudy (kendricklamar2014):

Let: x = the length of the width, x>0 x + 5 = the length of the box x - 2 = the height of the box V = 150 ft^3 the volume The volume of a box is: V = width*length*height x(x + 5)(x - 2) = 150 x^3 + 3x^2 - 10x - 150 = 0 We notice that for x = 5 the x(x + 5)(x - 2) = 150 is true thus one solution is x = 5 x + 5 = 5 + 5 = 10 ft x - 2 = 5 - 2 = 3 ft The measurements for the box are: 5 ft, 10 ft and 3 ft.

OpenStudy (kendricklamar2014):

Does this make sens @_ashleeey

OpenStudy (anonymous):

yes thank you can you help with more? @KendrickLamar2014

OpenStudy (kendricklamar2014):

I have to go, sorry I can help you later tho :)

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