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What is the equation of the line that passes through (0, -2) and has a slope of 0? y = -2 y = 2 x = 2
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Plug it into point-slope form
\(\sf y - y_1 = m(x - x_1)\)
(0, -2) x1 y1 m = 0
Or point-intercept y=mx+b
since the y intercept is -2 ....
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\(\sf y + 2 = 0(x - 0)\)
Simplify
The right side equals 0
y + 2 = 0
Subtract 2 to both sides
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-2?
Yes, so we have: y = -2
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