Help with Inclination of Lines
Find the distance between the point (6, 2) and the line x + 1 = 0 (round your answer to the nearest tenth).
@amistre64 How do i put this into form Ax + By + C = 0? We are missing y
I know it looks like it already is
but we are missing y :/
@zepdrix
x+1=0 ,hence x=-1 , it is here |dw:1431121899768:dw|
the point (6,2) is here . Can you say what the distance between them? |dw:1431121998819:dw|
Between x+1=0 and 6,2?
"we are missing y" .... no, the coeff of y = 0 1x + 0y +1 = 0 is the same as: x+1 = 0
that is your question, right?
S: so this would mean we could put it into the equation: \[\frac{ (1)(6)+(0)(2)+1 }{ \sqrt{1^2} }\]
so \[ \frac{ 7 }{ 1 }\]
or 7 would be the answer?
Although the method is weird to me, it is correct. :)
What would your method be? Just wondering this one was in my textbook
|dw:1431122409856:dw|
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