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Mathematics 8 Online
OpenStudy (darkbluechocobo):

Help with Inclination of Lines

OpenStudy (darkbluechocobo):

Find the distance between the point (6, 2) and the line x + 1 = 0 (round your answer to the nearest tenth).

OpenStudy (darkbluechocobo):

@amistre64 How do i put this into form Ax + By + C = 0? We are missing y

OpenStudy (darkbluechocobo):

I know it looks like it already is

OpenStudy (darkbluechocobo):

but we are missing y :/

OpenStudy (darkbluechocobo):

@zepdrix

OpenStudy (loser66):

x+1=0 ,hence x=-1 , it is here |dw:1431121899768:dw|

OpenStudy (loser66):

the point (6,2) is here . Can you say what the distance between them? |dw:1431121998819:dw|

OpenStudy (darkbluechocobo):

Between x+1=0 and 6,2?

OpenStudy (amistre64):

"we are missing y" .... no, the coeff of y = 0 1x + 0y +1 = 0 is the same as: x+1 = 0

OpenStudy (loser66):

that is your question, right?

OpenStudy (darkbluechocobo):

S: so this would mean we could put it into the equation: \[\frac{ (1)(6)+(0)(2)+1 }{ \sqrt{1^2} }\]

OpenStudy (darkbluechocobo):

so \[ \frac{ 7 }{ 1 }\]

OpenStudy (darkbluechocobo):

or 7 would be the answer?

OpenStudy (loser66):

Although the method is weird to me, it is correct. :)

OpenStudy (darkbluechocobo):

What would your method be? Just wondering this one was in my textbook

OpenStudy (loser66):

|dw:1431122409856:dw|

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