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What is the value of the expression? 5^-6 * 5^2/5^8
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Here are some basic rules that you need to consider \(\Large a^b*a^c=a^{b+c}\) \(\LARGE \frac{ a^b}{a^c}=a^{b-c}\)
First, work on the numerator by using \(\Large a^b*b^c=a^{b+c}\) Then do the division exponent rule.
Makes sense?
Hmmm kinda
Try working this out on here or on paper then type down what you got.
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Otay :)
\(\LARGE \frac{5^{-6} * 5^2}{5^8}\)=?
\(\LARGE \frac{5^{-6+2}}{5^8}\)
And i'll leave the rest to you
Okay thank you :)
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Anytime~
So is it 5^-12
I forgot to add the negative in 5^8 it was actually 5^-8
hello? ;_;
\(\LARGE \frac{5^{-6+2}}{5^{-8}}=\frac{5^{-4}}{5^{-8}}=5^{-4-(-8)}=5^{-4+8}=5^{4}\)
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Oh thank I understand now :) ♥♥♥
No problem :)
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