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Mathematics
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OpenStudy (anonymous):
CAN ANYONE HELP? :D
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OpenStudy (anonymous):
OpenStudy (anonymous):
I can complete the square but after that I don't know what to do.
OpenStudy (anonymous):
this is the complete square
OpenStudy (anonymous):
What is the form? @dan815
OpenStudy (welshfella):
first divide the coefficient of x by 2
this will tell you what a is in ( x + a)^2
can you do that?
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OpenStudy (welshfella):
we have x^2 + 12x + 31 = 0
what is the coefficient of x in this equation?
OpenStudy (welshfella):
what multiplies x?
OpenStudy (welshfella):
hello? r u there?
OpenStudy (anonymous):
I am now, sorry
OpenStudy (anonymous):
@welshfella
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OpenStudy (anonymous):
i have the x, i just need to know the form
OpenStudy (anonymous):
@dan815 @Nnesha @incomplte @TheSmartOne
OpenStudy (welshfella):
x^2 + 12x + 31 = 0
divide the 12 by 2 = 6
(x + 6)^2 - 36 + 31 = 0
(its -36 because (x + 6)^2 = x^2 + 12x + 36)
(x + 6)^2 - 5 = 0
(x + 6)^2 = 5
now you need to take the square root of both sides
OpenStudy (welshfella):
remember that there is a positive and negative square root
OpenStudy (welshfella):
the solution set is {-6+sqrt5 , -6 - sqrt5}
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OpenStudy (welshfella):
the form is (x + 6)^2 = 5
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