Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

CAN ANYONE HELP? :D

OpenStudy (anonymous):

OpenStudy (anonymous):

I can complete the square but after that I don't know what to do.

OpenStudy (anonymous):

this is the complete square

OpenStudy (anonymous):

What is the form? @dan815

OpenStudy (welshfella):

first divide the coefficient of x by 2 this will tell you what a is in ( x + a)^2 can you do that?

OpenStudy (welshfella):

we have x^2 + 12x + 31 = 0 what is the coefficient of x in this equation?

OpenStudy (welshfella):

what multiplies x?

OpenStudy (welshfella):

hello? r u there?

OpenStudy (anonymous):

I am now, sorry

OpenStudy (anonymous):

@welshfella

OpenStudy (anonymous):

i have the x, i just need to know the form

OpenStudy (anonymous):

@dan815 @Nnesha @incomplte @TheSmartOne

OpenStudy (welshfella):

x^2 + 12x + 31 = 0 divide the 12 by 2 = 6 (x + 6)^2 - 36 + 31 = 0 (its -36 because (x + 6)^2 = x^2 + 12x + 36) (x + 6)^2 - 5 = 0 (x + 6)^2 = 5 now you need to take the square root of both sides

OpenStudy (welshfella):

remember that there is a positive and negative square root

OpenStudy (welshfella):

the solution set is {-6+sqrt5 , -6 - sqrt5}

OpenStudy (welshfella):

the form is (x + 6)^2 = 5

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!