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Mathematics 7 Online
OpenStudy (anonymous):

taken down temporarily

OpenStudy (xapproachesinfinity):

the discriminant is \[\Delta =b^2-4ac=5^2-4(1)(4)=25-16=9\]

OpenStudy (xapproachesinfinity):

what does that tell you

OpenStudy (anonymous):

Okay I understand that I think! That's the discriminant part of the quadratic formula. What about part B and C? I forgot how to complete the square :(

OpenStudy (anonymous):

Are you still there?

OpenStudy (anonymous):

@bleebleebleed

OpenStudy (anonymous):

is it multiple choice?

OpenStudy (anonymous):

no sadly not

OpenStudy (anonymous):

lets see

OpenStudy (anonymous):

I have part A down, just need part B and C if you have time

OpenStudy (anonymous):

I have a website that should help you try www.mathway.com or jiskha.com

OpenStudy (anonymous):

to graph it?

OpenStudy (anonymous):

im bad at math

OpenStudy (anonymous):

mathway

OpenStudy (anonymous):

mathway allows u too graph it

OpenStudy (anonymous):

I know what mathway is but do you know how to complete the square?

OpenStudy (anonymous):

what grade are you in?

OpenStudy (anonymous):

9th this is Algebra

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

ill have my sister help you she should know

OpenStudy (anonymous):

is she on now? thank you!

OpenStudy (anonymous):

your welcome lemme tag her

OpenStudy (anonymous):

@Sam_Aka_Sara

OpenStudy (anonymous):

she is online?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

okay awesome thank you, if she doesn't reply that quickly I'll try and have someone else help cause I'm timed xc

OpenStudy (anonymous):

shes viewing it

OpenStudy (anonymous):

yay awesome

OpenStudy (anonymous):

ok i got it

OpenStudy (anonymous):

you do? awesome please show me how

OpenStudy (anonymous):

@jsmusic3

OpenStudy (anonymous):

@AaronAndyson

OpenStudy (quickthing):

1. A quadratic equation is shown below: x2 + 5x + 4 = 0 Part A Discriminant, D = (5)^2 - 4{1)(4) = 25 - 16 = 9 Since D > 0, equation has two distinct rational roots : - 1 and - 4

OpenStudy (quickthing):

@nincompoop

OpenStudy (anonymous):

I have that down but what about B and C?

OpenStudy (quickthing):

Equation can easily be factorised 4x2 -12x + 5 = 0 (2x - 1)(2x - 5) = 0 2x - 1 = 0 or 2x - 5 = 0 x = 1/2 , 5/2

OpenStudy (anonymous):

That's all to that one?

OpenStudy (quickthing):

For B

OpenStudy (quickthing):

Part C By completing the square 2x^2 -10x + 3 = 0 x^2 - 5x + 3/2 = = (x - 5/2)^2 - 25/4 + 3/2 = 0 (x - 5/2)^2 - 19/4 = 0 (x - 5/2)^2 = 19/4 x - 5/2 = +/- sqrt(19/4) x = 5/2 +/-sqrt(19/4) = 4.68, 0.32

OpenStudy (anonymous):

ok then nvm

OpenStudy (anonymous):

thank you for at least trying bleebleebleed and oh my gosh thank you so much quickthing! how do I give medals to both you guys? I'm really new to this lol

OpenStudy (quickthing):

Click best answer. No need to give me a medal though c:

OpenStudy (anonymous):

I do! You helped me lots! What math class do you take? cx

OpenStudy (quickthing):

The math class of doom. :P

OpenStudy (quickthing):

I would rather forget math during weekends XD

OpenStudy (anonymous):

I meant in school lmao but you're really good c'x

OpenStudy (quickthing):

Not really. Take a look. https://answers.yahoo.com/question/index?qid=20140414100611AALyX7f

OpenStudy (anonymous):

is that the one I had?

OpenStudy (quickthing):

I believe so.

OpenStudy (quickthing):

1. A quadratic equation is shown below: x2 + 5x + 4 = 0 Part A: Describe the solution(s) to the equation by just determining discriminant. Show your work. (3 points) Part B: Solve 4x2 -12x + 5 = 0 using an appropriate method. Show the steps of your work and explain why you chose the method used. (4 points) Part C: Solve 2x2 -10x + 3 = 0 by using a method different from the one you used in Part B. Show the steps of your work. (3 points)

OpenStudy (anonymous):

well I don't understand why I should graph the first one it doesn't answer anything

OpenStudy (quickthing):

Math is weird. If I can 'help' more, let me know c:

OpenStudy (anonymous):

yeah lmao it really is. But yeah I will! I'll take your word for it on these questions, talk to you later! c:

OpenStudy (quickthing):

Okie c:

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