An equation is shown below:

5(2x - 3) = 5

Part A: How many solutions does this equation have?

Part B: What are the solutions to this equation? Show your work.

Question

An equation is shown below:

5(2x - 3) = 5

Part A: How many solutions does this equation have?

Part B: What are the solutions to this equation? Show your work.

kidrah69 · Answer

Ok so first lets solve it :) do you know where to start?

kidrah69 · Answer

Hint: Start with distributing.

xapproachesinfinity · Answer

see 5 in the left and right
can you do something about it?

anonymous · Answer

i don't know how to do these at all

xapproachesinfinity · Answer

why?

xapproachesinfinity · Answer

you don't know is not good enough

kidrah69 · Answer

Multiply 5 by whats in the paranthese's

xapproachesinfinity · Answer

before that just multiply by 1/5 both sides of the equation to eliminate 5

kidrah69 · Answer

Well you can do that at the end too :/

xapproachesinfinity · Answer

$$5(2x-3)=5 \Longrightarrow \frac{1}{5}5(2x-3)=\frac{1}{5}5$$
so 2x-3=1

xapproachesinfinity · Answer

yeah you can to do that a well no problem just good to eliminate things as soon as possible

anonymous · Answer

you did not read the problem correctly that's not what i need

playgames1122 · Answer

part A 
10x-15=5
                       10x = 5+15
                               x= 20/10
                                  x=2