Question

Write the equation of a circle with a center at (0, 8) and a radius of 9.


would my answer be: (x-0)^2 +(y-8)^2=6 ???

Answer 1

Not 6.. I meant 9

Answer 2

close

\(\bf 3^2=9\qquad thus
\\ \quad \\
(x-{\color{brown}{ 0}})^2+(y-{\color{blue}{ 8}})^2={\color{purple}{ 3}}^2

\qquad center\ ({\color{brown}{ 0}},{\color{blue}{8}})\qquad
radius={\color{purple}{ 3}}\)

Answer 3

Im sorry, just a bit confused. How did you get 3?

Answer 4

ohh the radius is hmmm
hold the mayo

Answer 5

hmmm the radius is just 9 flat... I see
thus \(\bf (x-{\color{brown}{ 0}})^2+(y-{\color{blue}{ 8}})^2={\color{purple}{ 9}}^2\)

sorta misread above =(

Answer 6

I was going to say,
your "6" is correct, if you just put it upside-down =)

Answer 7

its fine :)


if i dont put the ^2 would it be considered wrong??

Answer 8

on the radius

Answer 9

yes

the radius is there, but squared
the wording above says that "the radius is 9"

so that makes it \(\large = 9^2\)

Answer 10

okay cool thanks for your help!

Answer 11

yw