Question

Can someone help me with this question?

Answer 1

I got this: 1.03798112

Answer 2

What base is the log? base 10 or base e?

Answer 3

Ok let's assume it's base e.
We can use the identity log(m) - log(n) = log(m/n). Then what do we do?

Answer 4

hmmm ...... divide

Answer 5

Well, what do we have?
\[\log(\frac{ 3x }{ 13 }) = 2\]

Answer 6

How do we get rid of the log, assuming it's base is e?

Answer 7

I dont know
but I think its x=1300 / 3

Answer 8

Where did you get that from?
Anyway, the next step would be to rearrange the equation, knowing if log_b(y) = x, then y = e^x

Answer 9

Ok it looks like your answer is right, but that would assume that the base is 10.

Answer 10

i just worked it

Answer 11

but I dont know how to imply my answer to get the right anwser

Answer 12

What do you mean by "implying" your answer?
I think your answer IS right, if the base of the log is 10.

Following on from my previous equation, we would have 3x/13 = 10^2, and we just rearrange that to find x, which would be 1300/3 (as you said) and that is equal to 433.333

Answer 13

oh ok we re-arrange gotcha