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OpenStudy (surana):
Hang on, I need to post it.
OpenStudy (surana):
OpenStudy (surana):
There.
OpenStudy (isaiah.feynman):
Do you know of the roots of a quadratic?
OpenStudy (surana):
Kind of?
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OpenStudy (isaiah.feynman):
Okay, when you graph a quadratic, the points where the graph intersect the x axis are called the roots. Can you determine the roots of your graph?
OpenStudy (surana):
4 and 6?
OpenStudy (isaiah.feynman):
Good. Usually we say the roots are x = 4 and x = 6. Remember how you can factor a quadratic equation down to getting values for x?
OpenStudy (surana):
Could you refresh my memory?
OpenStudy (isaiah.feynman):
Sure. To do that we must factor a quadratic now. Take a simple example. \[x^{2} + 4x + 4 = 0\] is factored to \[(x+2)(x+2) = 0\] which means \[x = -2, -2\]
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OpenStudy (surana):
Okay.
OpenStudy (isaiah.feynman):
See how I went from the equation to the x values? in your problems we will go from the x values back to the original equation.
OpenStudy (surana):
Yes, I see what you did.
OpenStudy (isaiah.feynman):
From your graph, we see that \[x = 4, 6\]What is the next step upward using my example?
OpenStudy (surana):
x^2 + 4 +6?
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OpenStudy (isaiah.feynman):
Not quite, take it step by step. If x = 4,6 This means that \[(x-4)(x-6) = 0\]
OpenStudy (surana):
Okay.
OpenStudy (isaiah.feynman):
Understand what I did?
OpenStudy (surana):
Sort of.
OpenStudy (surana):
But I do understand some of it.
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OpenStudy (isaiah.feynman):
What we are going to do now is to expand this expression. \[(x-4)(x-6) = 0\]Remember how to do that?
OpenStudy (surana):
Yeah!
OpenStudy (isaiah.feynman):
Lets see you do it.
OpenStudy (surana):
(x^2 - x + 24)
OpenStudy (surana):
No wait. Hang on. I do this better on paper...
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OpenStudy (surana):
x - 4x + 24
OpenStudy (isaiah.feynman):
Try this, do you remember distributing?
OpenStudy (surana):
It's that thing where you spread out the numbers across a parentheses set, isn't it?
OpenStudy (isaiah.feynman):
Yep. So let's do this. \[x(x-6)-4(x-6)\]You will distribute the x and the -4 across the parentheses.
OpenStudy (surana):
x^2 and 6x, and -4x and +24?
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OpenStudy (isaiah.feynman):
Yes, yes. Now add everything together taking signs into consideration.
OpenStudy (surana):
So it'd be x^2 +2x + 24?
OpenStudy (isaiah.feynman):
Oh, I noticed a mistake, there should be a negative beside the 6x because x multiplies -6
OpenStudy (surana):
Oh. Yeah. I was wondering about that since how we got to the negative part was confusing me.
OpenStudy (isaiah.feynman):
Okay. Now the mistake is cleared, what is the new correct expression?
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OpenStudy (surana):
x^2 - 2x + 24?
OpenStudy (isaiah.feynman):
Not quite. \[x(x-6)-4(x-6) = x^{2}-6x \space\and\ -4x+24\]
OpenStudy (surana):
Oh.
OpenStudy (isaiah.feynman):
Now add them together, gives you \[x^{2} -10x+24=0\]
OpenStudy (surana):
So that's the answer?
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