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Mathematics 18 Online
OpenStudy (surana):

What is the equation of the following graph?

OpenStudy (surana):

Hang on, I need to post it.

OpenStudy (surana):

OpenStudy (surana):

There.

OpenStudy (isaiah.feynman):

Do you know of the roots of a quadratic?

OpenStudy (surana):

Kind of?

OpenStudy (isaiah.feynman):

Okay, when you graph a quadratic, the points where the graph intersect the x axis are called the roots. Can you determine the roots of your graph?

OpenStudy (surana):

4 and 6?

OpenStudy (isaiah.feynman):

Good. Usually we say the roots are x = 4 and x = 6. Remember how you can factor a quadratic equation down to getting values for x?

OpenStudy (surana):

Could you refresh my memory?

OpenStudy (isaiah.feynman):

Sure. To do that we must factor a quadratic now. Take a simple example. \[x^{2} + 4x + 4 = 0\] is factored to \[(x+2)(x+2) = 0\] which means \[x = -2, -2\]

OpenStudy (surana):

Okay.

OpenStudy (isaiah.feynman):

See how I went from the equation to the x values? in your problems we will go from the x values back to the original equation.

OpenStudy (surana):

Yes, I see what you did.

OpenStudy (isaiah.feynman):

From your graph, we see that \[x = 4, 6\]What is the next step upward using my example?

OpenStudy (surana):

x^2 + 4 +6?

OpenStudy (isaiah.feynman):

Not quite, take it step by step. If x = 4,6 This means that \[(x-4)(x-6) = 0\]

OpenStudy (surana):

Okay.

OpenStudy (isaiah.feynman):

Understand what I did?

OpenStudy (surana):

Sort of.

OpenStudy (surana):

But I do understand some of it.

OpenStudy (isaiah.feynman):

What we are going to do now is to expand this expression. \[(x-4)(x-6) = 0\]Remember how to do that?

OpenStudy (surana):

Yeah!

OpenStudy (isaiah.feynman):

Lets see you do it.

OpenStudy (surana):

(x^2 - x + 24)

OpenStudy (surana):

No wait. Hang on. I do this better on paper...

OpenStudy (surana):

x - 4x + 24

OpenStudy (isaiah.feynman):

Try this, do you remember distributing?

OpenStudy (surana):

It's that thing where you spread out the numbers across a parentheses set, isn't it?

OpenStudy (isaiah.feynman):

Yep. So let's do this. \[x(x-6)-4(x-6)\]You will distribute the x and the -4 across the parentheses.

OpenStudy (surana):

x^2 and 6x, and -4x and +24?

OpenStudy (isaiah.feynman):

Yes, yes. Now add everything together taking signs into consideration.

OpenStudy (surana):

So it'd be x^2 +2x + 24?

OpenStudy (isaiah.feynman):

Oh, I noticed a mistake, there should be a negative beside the 6x because x multiplies -6

OpenStudy (surana):

Oh. Yeah. I was wondering about that since how we got to the negative part was confusing me.

OpenStudy (isaiah.feynman):

Okay. Now the mistake is cleared, what is the new correct expression?

OpenStudy (surana):

x^2 - 2x + 24?

OpenStudy (isaiah.feynman):

Not quite. \[x(x-6)-4(x-6) = x^{2}-6x \space\and\ -4x+24\]

OpenStudy (surana):

Oh.

OpenStudy (isaiah.feynman):

Now add them together, gives you \[x^{2} -10x+24=0\]

OpenStudy (surana):

So that's the answer?

OpenStudy (isaiah.feynman):

That's the equation of your graph.

OpenStudy (surana):

Thank you.

OpenStudy (isaiah.feynman):

No problems.

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