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Mathematics 9 Online
OpenStudy (anonymous):

limits?

OpenStudy (anonymous):

OpenStudy (anonymous):

its 12/0 or just 12

OpenStudy (anonymous):

so divide 12 by 0 and thats ur answer

OpenStudy (anonymous):

factorise

OpenStudy (anonymous):

this will make it easy to solve

OpenStudy (anonymous):

i got tis

OpenStudy (anonymous):

what will be the factor of \[\huge x^2+3x-10\]

OpenStudy (anonymous):

@secretslocked please answer

OpenStudy (anonymous):

It is easy just factorise then the denominator will get cancelled

OpenStudy (irishboy123):

TYPO divide by x - 2

OpenStudy (anonymous):

uh 0?

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

the answer is 0 @secretslocked

OpenStudy (anonymous):

\[\huge \lim_{x \rightarrow 2}\frac{ x^2+3x-10 }{ x-2 }\] \[\huge \lim_{x \rightarrow 2}\frac{ x^2+5x-2x-10 }{ x-2 }\] \[\huge \lim_{x \rightarrow 2}\frac{ x(x+5)-2(x+5) }{ x-2 }\] \[\huge \lim_{x \rightarrow 2}\frac{ (x+5)(x-2) }{ x-2 }\] \(\huge\color{red}{Now\ continue }\)

OpenStudy (anonymous):

@behappy THE ANSWER IS 0

OpenStudy (anonymous):

@pandaluvs The ans is \(\Huge\ Not\) \(\large Zero\)

OpenStudy (anonymous):

@eta @amistre64 can you please help

OpenStudy (anonymous):

You have one (x-2) in numerator and one (x-2) in denominator, can't you cancel them out?

OpenStudy (anonymous):

please explain them that the answer is not zero i know the answer!

OpenStudy (welshfella):

yes cancel them out

OpenStudy (anonymous):

read the whole post

OpenStudy (welshfella):

after cancellimg you are left with x + 5

OpenStudy (anonymous):

@behappy be happy buddy.. :)

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

its 0

OpenStudy (anonymous):

0

OpenStudy (anonymous):

0

OpenStudy (welshfella):

so limit as x approaches 2 of x + 5 = ?

OpenStudy (anonymous):

NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO ITS ZEROOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

3?

OpenStudy (anonymous):

Behave like a Student please.. @Kainui

OpenStudy (anonymous):

@welshfella 3 ?

OpenStudy (welshfella):

2 + 5 = ?

OpenStudy (anonymous):

5 candy + 2 candy = how many candis?

OpenStudy (welshfella):

its simple - just plug in x = 2 into x + 5

OpenStudy (welshfella):

lol

OpenStudy (anonymous):

@secretslocked please ans

OpenStudy (anonymous):

7?

OpenStudy (welshfella):

hey!!!!! yes!!!!!

OpenStudy (anonymous):

wow!

OpenStudy (anonymous):

i feel stupid.

OpenStudy (welshfella):

check the above link to confirm it

OpenStudy (anonymous):

it says 5

OpenStudy (anonymous):

lol thx @eta and @welshfella

OpenStudy (anonymous):

@welshfella it says 5

OpenStudy (anonymous):

@welshfella limits tends to \(\Huge\ 2 \) not 0

OpenStudy (anonymous):

@welshfella correct it please

OpenStudy (welshfella):

oh yes i put x approaches 0 sorry for x approaches 2 it is of course 7

OpenStudy (anonymous):

last question; plz help i think my answer is wrong

OpenStudy (welshfella):

rest assured @secretlocked the answer to your question is 7

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