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Statistics 19 Online
OpenStudy (anonymous):

Statistics Help Please

OpenStudy (amistre64):

dont we expect that 44% of 1400 define the mean of the sample?

OpenStudy (anonymous):

So 616 would be the mean? 0.44*1400?

OpenStudy (amistre64):

yes

OpenStudy (amistre64):

consider this as a binomial distribution, what is the standard deviation for a binom distribution?

OpenStudy (amistre64):

mean = np sd = ???

OpenStudy (anonymous):

Is the formula Square root of p(1-p)/n or the square root of np(1-p)? I am stuck between those two.

OpenStudy (amistre64):

sqrt(npq) and we can get to that using proportions, but thats prolly immaterial

OpenStudy (amistre64):

since np = mean ... is 616 sqrt(616(.56))

OpenStudy (anonymous):

18.57

OpenStudy (amistre64):

yeah, that works for me

OpenStudy (anonymous):

Alright thank you!

OpenStudy (amistre64):

youre welcome

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