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dont we expect that 44% of 1400 define the mean of the sample?
So 616 would be the mean? 0.44*1400?
yes
consider this as a binomial distribution, what is the standard deviation for a binom distribution?
mean = np sd = ???
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Is the formula Square root of p(1-p)/n or the square root of np(1-p)? I am stuck between those two.
sqrt(npq) and we can get to that using proportions, but thats prolly immaterial
since np = mean ... is 616 sqrt(616(.56))
18.57
yeah, that works for me
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Alright thank you!
youre welcome
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