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Help please!
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Solve for B, C, and a
you can find `a` using law of cosines
Okay, I'll do that one first then
do you guys mind helping me when your done here?
I got 2.174 for a. Is that correct?
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@perl
4^2 + 6^2 - 2(4)(6)cos(10 degrees) = a^2 √(4^2 + 6^2 - 2(4)(6)cos(10 degrees) ) = a a = 2.17467879362
yes that is correct
now we need to find angle B and angle C
you can use law of sines
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The law of sines formula is a=b (sina)/(sinB), right?
Okay so I got 28.64 for one of the angles, but that means the other angle would be 121.36 ?
@perl
how many degrees must a triagnle have?
180
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@Poop_Emoji
so all the angles must add up to 180, right?
Yep
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