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convert cartesian equation of the line to parametric (image attached) when I do it, I keep missing 5s all over the place and its really annoying /:
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To me, \(5(x+(1/5)) = -5(y -(9/5) = -5z\) divide all by -5 \(\dfrac{x+(1/5)}{-1}=\dfrac{y-(9/5)}{1}=\dfrac{z}{1}\) hence \(x_0= (-1/5), a =-1\) \(y_0=(9/5) , b=1\) \(z_0=0, c =1\) Now, we can jot down the parametric equation \(x = x_0+ at\\y=y_0+ bt\\z = z_0+ct\)
oh so thats where the 5 comes from.. ok thanks!! I figured it out a different way :)
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