Question

http://prntscr.com/749yqz

Answer 1

@rvc

Answer 2

First, the area of the semi-circle would be
(PI * r^2)/2=
(PI*7*7)/2=
(22/7) * (7*7)/2 =
22*7/2

Answer 3

77

Answer 4

@wolf1728

Answer 5

We have to figure out the additional area (see graphic)

Answer 6

Area of 1/2 the square = 7 * 14
=98

Area of the semi-circle=77

So, the area of the red area (in the top half of the diagram) =
98-77 =
21

So, area of shaded area =
77 + 21 =98

Answer 7

I Didn't get the last bit?

Answer 8

Okay I redrew the graphic

Answer 9

Just looking at the top half of the square, wee have to calculate those 2 red areas correct?

Answer 10

#JustGotLost

Answer 11

So you agree we have to calculate those 2 red areas in the upper half of the circle?

Answer 12

I'm confused
Restart plx

Answer 13

I mean upper half of the SQUARE

Answer 14

Okay, right from the beginning
we calculated the area of the semi-circle which is 77 right?

Answer 15

Yes

Answer 16

What remains is that we have to calculate the area of the 2 red sections in the NEW graphic.

Answer 17

Yes

Answer 18

Okay the area of the entire area of the upper half of that square if 7 * 14 or 98 correct?

Answer 19

ACDE?
Yes

Answer 20

Yes ACDE = 98
Now we calculate the area of the semi-circle which we know is 77

Answer 21

Yes

Answer 22

So the area of the 2 red areas is 98 minus 77 = 21
Therefore the area of the semi-circle plus the 2 red areas = 77 + 21 = 98

Answer 23

?

Answer 24

Okay looking at the original black and white graphic we have to calculate the gray area

Answer 25

Oh
sure
now?

Answer 26

Okay the gray area in the upper half of the black and white graphoc equals the area of the 2 red areas in my recent graphic correct?

Answer 27

I think

Answer 28

Yes my graphic is drawn from a different perspective from the black and white graphic but you can see that the areas are the same right?

Answer 29

yES

Answer 30

So to get the area of those upper 2 red sections in my graphic, you get the area of the top half of the red square (7*14) =98 then subtract the area of the semi-circle 77 which equals 21

Answer 31

YES

Answer 32

So to solve the TOTAL area we get the 21 and add it to the semi-circle area (77) and we get 98

Answer 33

Yes

Answer 34

and that's it!

Answer 35

Can u summariaze it?

Answer 36

summarize*

Answer 37

okay maybe I should redraw the original graphic

Answer 38

sure

Answer 39

Wow - finally

Answer 40

now?

Answer 41

I think I've got an EASY explanation.
The red areas in the bottom half equal the gray areas in the top half

Answer 42

According to this book the shaded region i s98cm^2 :/

Answer 43

is*

Answer 44

Which we already calculated right?

Answer 45

No,The 98 we calculated is ACDE

Answer 46

Yes but that is ALSO the area of the semi-circle plus the 2 red areas.

Answer 47

I just can't understand this problem :/

Answer 48

We need to calculate the gray area
The semi-circle area is 77
The red areas equal 21
We add 77 + 21 = 98

Answer 49

What?
X_x

Answer 50

We proved (many lines ago) that the gray area of the upper half of the square equals the red area

Answer 51

es

Answer 52

Yes*

Answer 53

The red area = grey area = 21

Answer 54

U mean BED?

Answer 55

BED is the curved gray area and equals 21

Answer 56

ACDE = 98
BED = 21
EFD = 77
What about ABE & BCD

Answer 57

We didn't have to calculate ABE or BCD but they each equal 10.5

Answer 58

sO,WHAT NEXT?

Answer 59

We know the red areas = the grey areas in the upper half of the square

Answer 60

k

Answer 61

Area of the upper half of the square = 7 * 14 = 98
Area of semi-circle = 77
Area of upper gray areas = 98-77 = 21

Answer 62

After 2 hrs(inclusive of ur 1 hr) I finally got This one.

Answer 63

Okay - then I guess I can leave this question

Answer 64

Thanks
and yes

Answer 65

u r welcome :-)