Question

CAN SOMEONE PLEASE HELP ME!!

Answer 1

@Voltage

Answer 2

what value makes the denominator zero, that is the veritcal asymptote

the degree of the numerator and denominator is the same...

so find the value of th coefficients 3/(-3) =

if you need to check you can graph it using

https://www.desmos.com/calculator

Answer 3

oops forgot to say the horizontal asymptote is the value of 3/(-3) =

the vertical is where -3x + 6 = 0

Answer 4

I have no clue how to do this at all. Like I dont even know where to start

Answer 5

@dan815

Answer 6

@MrNood

Answer 7

@Mateaus

Answer 8

@MeganLeex3
You have been given a clear guidance by @Campbell_st above.

The only thing further he can do is give you the answer - which
a) is against the code of conduct
b) doesn't help you at al,l as you will not understand more having been given the answer.

If you TRULY have no clue where to start then you need to go back to your class , your text, your teacher and begin to understand the basics.

Here is a link to help find horizontal asymptotes , with a good explanation of WHY they can be found using the given method:
http://www.freemathhelp.com/finding-horizontal-asymptotes.html

Vertical asymptotes occur where the denominator is zero, and @Campbell_St has told you how to calculate this, above

Answer 9

my online class has no text book and no lessons. you literally have to figure out everything on your own, I have never seen anything like this therefore I do not know how to set anything up or what it is even supposed to look like. hence I dont know where to start.

Answer 10

start with the help given by me and Campbell above

Answer 11

do you know what an asymptote IS?

Answer 12

no

Answer 13

Well then you cannot answer this question.

You must find a text, a teacher a class or a web page (LIKE THE ONE I LINKED) and do some studying.

How can you be 'guided' to the answer to a question like this if oyu do not hav eht basic concepts of the question?