Mathematics
9 Online
OpenStudy (anonymous):
Find the derivative of f(x) = -2x^2 + 11x at x=9
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OpenStudy (anonymous):
can someone help me solve this while we use the formula
\[\lim_{h \rightarrow 0} \frac{ f(x+h)-f(x) }{ h } \]
OpenStudy (anonymous):
I somehow do not know how to set it up properly
OpenStudy (anonymous):
can you help me @Loser66
OpenStudy (loser66):
f(x+h)=??
OpenStudy (anonymous):
f(x+h) = -2(x+h)^2+11x?
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OpenStudy (loser66):
\(f(x+h)= -2(x+h)^2 +11(x+h)\)
OpenStudy (anonymous):
why is there another (x+h)? what about the -f(x) part?
OpenStudy (loser66):
because f(x) = -2x^2 +11x
hence, when replace x by x +h, you MUST replace all x on the expression
OpenStudy (anonymous):
okay, so instead of x its (x+h), but in the formula are we still going to use the other top half -f(x)?
OpenStudy (anonymous):
would it be -2(x+h)^2+11(x+h) - (-2x^2+11x)/ h?
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OpenStudy (loser66):
yup, open parentheses, simplify . What do you have?
OpenStudy (anonymous):
okay let me see
OpenStudy (anonymous):
-4hx - 2h^2 + 11h?
OpenStudy (loser66):
you forgot h at the denominator. That is just numerator.
From it, factor h out, cancel out with h in denominator, what do you have?
OpenStudy (anonymous):
yeah i meant just the numerator lol
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OpenStudy (anonymous):
if i cancel the h, i would have -4x - 2h + 11
OpenStudy (anonymous):
would i now replace h with 0?
OpenStudy (loser66):
Hold on, your calculation is not correct. Let check
OpenStudy (anonymous):
oh sorry
OpenStudy (anonymous):
would i take -h out and have 4x + 2h - 11?
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OpenStudy (loser66):
oh, you are correct
OpenStudy (loser66):
no need to take - out, just h
OpenStudy (anonymous):
okay i was confused for a second
OpenStudy (loser66):
cancel out, and get -4x -2h +11. Now take lim when h --> 0 we have -4x +11 , replace x =9. Dat sit
OpenStudy (anonymous):
-25
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OpenStudy (loser66):
yup
OpenStudy (anonymous):
that should be it! I get it better now! Thank you very very much!
OpenStudy (loser66):
np