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OpenStudy (darkbluechocobo):
Help with finding the angle between two lines
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OpenStudy (darkbluechocobo):
Find the angle between the following two lines:
x − y = 0
3x − 2y = negative-1
(round your answer to the nearest tenth of a degree).
OpenStudy (darkbluechocobo):
y=x
y=3/2x+.5
OpenStudy (darkbluechocobo):
3/2-1= 1/2
3/2(1)+1=5/2
OpenStudy (darkbluechocobo):
\[\tan^{-1}(\frac{ 1/2 }{5/2 })\]
OpenStudy (freckles):
is negative-1 means 1?
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OpenStudy (freckles):
or did you mean to write one negative?
OpenStudy (darkbluechocobo):
No copy and paste didn't work well lool
OpenStudy (darkbluechocobo):
3x-2y=-1
OpenStudy (freckles):
\[y=x \text{ has slope } m_1=1 \\ 3x-2y=-1 \rightarrow -2y=-3x-1 \rightarrow y=\frac{3}{2}x+\frac{1}{2} \text{ has slope } m_2=\frac{3}{2} \\ m_2-m_1=\frac{3}{2}-1=\frac{1}{2} \\ 1+m_2 \cdot m_1 =1+\frac{3}{2} \cdot 1=\frac{5}{2}\]
so yes your setup is right
OpenStudy (darkbluechocobo):
yay I got 11.3 degrees
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OpenStudy (freckles):
sounds great
OpenStudy (darkbluechocobo):
Thank you for checking my work ^_^ finally am getting it down with no errors
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