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Mathematics 14 Online
OpenStudy (darkbluechocobo):

Help with finding the angle between two lines

OpenStudy (darkbluechocobo):

Find the angle between the following two lines: x − y = 0 3x − 2y = negative-1 (round your answer to the nearest tenth of a degree).

OpenStudy (darkbluechocobo):

y=x y=3/2x+.5

OpenStudy (darkbluechocobo):

3/2-1= 1/2 3/2(1)+1=5/2

OpenStudy (darkbluechocobo):

\[\tan^{-1}(\frac{ 1/2 }{5/2 })\]

OpenStudy (freckles):

is negative-1 means 1?

OpenStudy (freckles):

or did you mean to write one negative?

OpenStudy (darkbluechocobo):

No copy and paste didn't work well lool

OpenStudy (darkbluechocobo):

3x-2y=-1

OpenStudy (freckles):

\[y=x \text{ has slope } m_1=1 \\ 3x-2y=-1 \rightarrow -2y=-3x-1 \rightarrow y=\frac{3}{2}x+\frac{1}{2} \text{ has slope } m_2=\frac{3}{2} \\ m_2-m_1=\frac{3}{2}-1=\frac{1}{2} \\ 1+m_2 \cdot m_1 =1+\frac{3}{2} \cdot 1=\frac{5}{2}\] so yes your setup is right

OpenStudy (darkbluechocobo):

yay I got 11.3 degrees

OpenStudy (freckles):

sounds great

OpenStudy (darkbluechocobo):

Thank you for checking my work ^_^ finally am getting it down with no errors

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