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Algebra 13 Online
OpenStudy (anonymous):

What is the equation of the ellipse with co-vertices (-20, 0), (20, 0) and foci (0, -8), (0, 8)?

OpenStudy (loser66):

@DarkBlueChocobo come here to play, you are the right person to solve it. practice on other's problem is the best way to confirm your knowledge.

OpenStudy (loser66):

@juliamae10 since I saw you post 2 exactly- the- same problem on 2 different sections, I assume that you just want the answer. If it is so, why don't we let other student who needs practice work out on your problem, right? both you guys get what you want.

OpenStudy (darkbluechocobo):

@Loser66 co vertices are they half of the vertices ?

OpenStudy (loser66):

@DarkBlueChocobo foci is about c, and it is on the vertical line, hence your main axis is y axix |dw:1431803368050:dw|

OpenStudy (darkbluechocobo):

Or am I getting mixed up between hyperbolas and parabolas

OpenStudy (loser66):

co-vertices is a minor one, not the long one

OpenStudy (darkbluechocobo):

so the length of the minor axis 20?

OpenStudy (loser66):

|dw:1431803420147:dw|

OpenStudy (loser66):

40, not 20

OpenStudy (loser66):

you find a by c^2 = a^2 -b^2

OpenStudy (loser66):

hence a^2 =??

OpenStudy (darkbluechocobo):

does c^2 = 8^2? @Loser66

OpenStudy (loser66):

yup

OpenStudy (darkbluechocobo):

b^2=20^2?

OpenStudy (loser66):

yup again

OpenStudy (darkbluechocobo):

8^2=a^2-20^2

OpenStudy (loser66):

yup

OpenStudy (loser66):

need a^2

OpenStudy (darkbluechocobo):

so -a^2=400-64 -a^2=336

OpenStudy (loser66):

hey

OpenStudy (darkbluechocobo):

Did i mess up with -a^2?

OpenStudy (loser66):

\(8^2 = a^2 -400\\a^2 = 8^2 +400\) just +400 both sides

OpenStudy (darkbluechocobo):

ohhhh that was simple: a=sqrt464

OpenStudy (loser66):

nope, let a^2 as it is. \(a^2 = 464\)

OpenStudy (loser66):

now, you have a^2, b^2, just plug all in formula for VERTICAL ellipse formula that is \(\dfrac{x^2}{b^2}+\dfrac{y^2}{a^2}=1\)

OpenStudy (darkbluechocobo):

\[\frac{ x^2 }{ 20^2}+\frac{ y^2 }{ 464^2 }=1\]

OpenStudy (loser66):

\[\frac{ x^2 }{ 400}+\frac{ y^2 }{ 464 }=1\]

OpenStudy (darkbluechocobo):

And that would be the equation

OpenStudy (loser66):

Remember, if it is HORIZONTAL ellipse, then the denominator of x term is a^2 if it is VERTICAL ellipse, the denominator of x term is b^2 They are different, that is why at the beginning, I have to define which one is the correct form by using foci and co-vertices.

OpenStudy (loser66):

yes, that is the required equation.

OpenStudy (darkbluechocobo):

Yes if the number is bigger under y that means that is it vertical

OpenStudy (loser66):

|dw:1431804460345:dw|

OpenStudy (darkbluechocobo):

if the bigger number is under x it is horizontal

OpenStudy (loser66):

ok, good job

OpenStudy (darkbluechocobo):

Thank you for leading me to solve it

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