Question

Here are the golf scores of 12 members of a college women's golf team in two rounds of tournament play. (A golf score is the number of strokes required to complete the course, so that low scores are better.) To what extent may we predict the second round score from the first round score? The standard error of the slope is 0.23.

SEE COMMENTS FOR GRAPH
a. Find a 95% confidence interval for the slope.

b. Find a 99% confidence interval for the slope

Answer 1

@amistre64 @kropot72 @jtvatsim

Answer 2

Hey @kropot72 How goes it?

Answer 3

@israa88 do you have any clue how to do this?

Answer 4

what grade is this for ?

Answer 5

12th grade AP Statistics

Answer 6

but AP stats can be taken by any high school grade

Answer 7

oh ill try my best i am only a freshmen in high school lol

Answer 8

ok. any help is better than none....

Answer 9

and I have a whole lot of nothing right now lol

Answer 10

awww lol we will come up with something

Answer 11

lol i hope so

Answer 12

http://stattrek.com/regression/slope-confidence-interval.aspx

Answer 13

that is what they gave us in the lesson and I am having trouble understanding how to apply by setting up the problem. I have trouble setting up an equation and putting the numbers in the right places. I have ADHD so my brain organizes things differently from other peoples which is one of the reasons why we have problems focusing on one task for an extended amount of time.... In other words, can we keep this as dumbed down as possible?

Answer 14

Hey don't say there is nothing wrong with have ADHD .. we will figure this out lol i am trying to read this stuff but man its hard

Answer 15

yeah

Answer 16

tell me about it, I took the AP exam today and this is my last assignment, but it's ust this one question

Answer 17

ill help u find someone that can help

Answer 18

@TheSmartOne

Answer 19

thank you

Answer 20

@xapproachesinfinity

Answer 21

lol no problem i don't see why you're thanking me i did nothing really

Answer 22

Because it's respectful and polite, and yes you did, you gave your time and a recommendation, therefore, thank you

Answer 23

well no problem.. thats what we're here for to help each other so its really no problem

Answer 24

i am going to find someone to help u even if i ended up tagging everyone

Answer 25

@Preetha @jim_thompson5910 @satellite73 @amistre64 @zepdrix

Answer 26

@kropot72 @jagr2713 @acxbox22 @misty1212

Answer 27

@HelpBlahBlahBlah @jabez177 @kidrah69

Answer 28

@hedgiemomma @Legends @vzfreakz @domebotnos

Answer 29

@satellite73

Answer 30

@xo_kansasprincess_xo

Answer 31

I have too much of my own work to do. Sorry.

Answer 32

its ok :) do u know someone who might be able to help us

Answer 33

@xapproachesinfinity

Answer 34

dang there services here suck @bookworm1156

Answer 35

@isry98

Answer 36

Nah..lol I can barely get any help myself :-/

Answer 37

yeah, well, I have to finish the class by tomorrow afternoon.... Maybe by then someone will respond

Answer 38

This is that last assignment and I am hoping that it will push my grade from a B to a C

Answer 39

Yep! I understand. I have to be done with everything by tomorrow morning at 8.

Answer 40

Ew. Yeah, No Bueno. I have to be done by Friday. That is the only reason why being a senior sucks. I really need to get a B in this course because I don't want to risk loosing my placement in my class

Answer 41

the formulas are not that pretty, and it looks like you might be better off with excel of some spread sheet program to find the values needed

im not sure, but i think they give you the top part already

\[\large \sqrt{\frac{s^2_e}{\sum (x-\bar x)^2}}\]

Answer 42

we of course need to determine the slope of the regression line:
\[\Large \hat B_1=\frac{n\sum xy -\sum x\sum y}{n\sum xx -\sum x\sum x}\]
\[\hat B_1 \pm t_{\alpha/2}\large \sqrt{\frac{s^2_e}{\sum (x-\bar x)^2}}\]

Answer 43

im not sure, but i think this might be asking for how well the regression model for round 1, fits for round 2.

if we regard the regression line in 1 as the mean, the variance can be determined by
sum (observed - y^) ^2
-------------------
n (or n-1)

but m not sure how well this fits in here

Answer 44

i see some sites saying n-2 ...

Answer 45

http://ncss.wpengine.netdna-cdn.com/wp-content/themes/ncss/pdf/Procedures/PASS/Confidence_Intervals_for_Linear_Regression_Slope.pdf

Answer 46

no we need to find a confidence interval for slope

Answer 47

So do you know the equation for a confidence interval

Answer 48

I think I can help you on this. Pretty Sure. I am currently taking stats. I only have 30 minutes though. I got an exam soon

Answer 49

I hope you reply soon

Answer 50

Well I'm pretty sure this is it http://www.maths.otago.ac.nz/home/resources/stat110/2013_Summer_School:_Lectures/Lecture_8_-_Confidence_Intervals,_Two_Samples,_Paired_Data.pdf
I believe.
You need to first decide which test you are using (kind of not really)
You know its paired because its two samples. It's one sample because they are comparing peoples results in two different time points
Then you need to find the t-statistic given for 12 people (so what is the degrees of freedom?), and the 95% aspect of it. (.025 on each tail)
Then you are done
So it looks like this
(meanround 2-mean round1)+/- T-statistic*standard error

Answer 51

I may check this later on in the day. Send me a message if you so which. I may be able to help more after my two exams. (I have another one tomorrow as well; I still need to study for it). But I am totally willing to help!

Answer 52

Sorry, I was in an important meeting

Answer 53

Ok

Answer 54

How did your exams go?

Answer 55

I do not have them yet. I am an in anticipation to begin them. One begins at 9 EST the other at 2. Both are 3 hour exams. How was your meeting?

Answer 56

Oh, well good luck! It went well, I was just meeting with my new college guidance counselor to set up my classes for fall semester:P

Answer 57

Cool Cool. So you are a Senior in high school? And did you understand what I said above for the question?

Answer 58

College exams? That's rough, luckily once you finish the test they let you leave though so it can be three hours for those who need it but most people finish them in an hour and a half

Answer 59

Yes I am. I graduate in less than three weeks. :) And yes I do.

Answer 60

My exams are quite long. Most people finish with around 10 minutes left.

Answer 61

But yay! Congrats!

Answer 62

Confidence Interval : statistic +/- (critical value) (standard deviation)

Answer 63

Geez! that's rough... I did dual enrollment this year and out exams were usually only about 2 hours long each. and thank you very much

Answer 64

What is this critical value?

Answer 65

What I struggle with is what goes where in equations (basically the organization of equations) so please correct me if I am wrong :

Answer 66

ok

Answer 67

df = n-2

Answer 68

12 - 2 = 10

Answer 69

for 95% - 2.228
for 99% - 3.169

Answer 70

is that correct?

Answer 71

@Gerardo_cast23

Answer 72

Yes I'm not sure if the degrees of freedom is correct. If that is what your instructor raught you then go with it. Different teachers say different df

Answer 73

I am an online student and they taught us using stattrek.com

Answer 74

@Gerardo_cast23 what do I need to look for next

Answer 75

What do you mean?

Answer 76

after finding the critical value what do I do next?

Answer 77

so now you have your statistic
So its
mean of group 2-mean of group 1 +/- critical value*standard error

Answer 78

I'm pretty sure that's it

Answer 79

I don't think so.... This is what they taught us with: http://stattrek.com/regression/slope-confidence-interval.aspx

Answer 80

This looks like a lot more work than just that

Answer 81

Hmm odd. I was taught What I am doing. I am almost positive it is correct with what I am saying.
I know this because we are conducting an analogous one paired sample t-test.
I'm not sure. I believe what I am saying is correct but I could be wrong.
(it's funny if I'm wrong too because my exam for stat is today haha).

Answer 82

lol I took my AP stat exam yesterday, it was really ew.

Answer 83

lol I'm sure you did fine

Answer 84

i don't think so :P but I feel confident enough to say I probably got a high 2

Answer 85

hahaha. Better than a 1

Answer 86

touche

Answer 87

Good luck! on the rest of your assignment hopefully I was of some help

Answer 88

yes you were