Suppose a bag contains 8 white chips and 2 black chips. What is the probability of randomly choosing a white chip, not replacing it, and then randomly choosing another white chip?

Question

anonymous · Answer

The first one is just going to be $$\frac{ number-of-white-chips }{ number-of-total-chips }$$ Then we take this and multiply it by $$\frac{ number-of-white-chips-minus-one }{ number-of-total-chips-minus-one }$$ Just substitute in numbers for the descriptions I provided.

anonymous · Answer

thank you very much

anonymous · Answer

No problem, what did you get for your answer? :)

anonymous · Answer

so if i plus in the numbers it would be 8 divided by 10 right

anonymous · Answer

Yes, do you know what that would simplify to?

anonymous · Answer

after i did everything i got 62/100 or 31/50

anonymous · Answer

No that would be wrong. The first section would be 4/5 and the second would be 7/9. Just multiply those fractions together.