What are the solutions to the equation x2 + 4 = 148?

A.
–11 and 11

B.
–2 and 2

C.
–12 and 12

D.
–4 and 4

Question

What are the solutions to the equation x2 + 4 = 148?
	
	
 
A.
	–11 and 11
	
 
B.
	–2 and 2
	
 
C.
	–12 and 12
	
 
D.
	–4 and 4

anonymous · Answer

@Chiko_1278

jaynator495 · Answer

by x2 do you mean $$\sf \Huge x^{2} $$

anonymous · Answer

i helped you already.....with this one...O.O

anonymous · Answer

First step is to rearrange the equation, getting everything on one side 

x^2 - 144 = 0 

At this point it's pretty clear what to do 

Difference of Perfect Squares 

(x+12)(x-12) = 0 

(x+12) = 0, (x-12) = 0 

x = -12, 12

anonymous · Answer

thats what i told you @posingocean

jaynator495 · Answer

Raise  x to the  2nd power
(x^2+4)-148=0 
Simplify x^2+4-148
(x+12)*(x-12)=0 
Solve (x+12)*(x-12)=0 
x+12 = 0 
Subtract  12  from both sides of the equation : 
x = -12 
x-12 = 0 
 Add  12  to both sides of the equation : 
 x = 12 

12 or -12

anonymous · Answer

ik i accidentally put this on here i had a diff question