Mathematics
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OpenStudy (anonymous):
please help... will fan and give medal
solve the equation cos 2θ+3 sin 2θ=2, for 0◦<θ<90◦.
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OpenStudy (anonymous):
expand cos2theta
OpenStudy (anonymous):
can you do the steps pls ??
OpenStudy (anonymous):
\[\cos2\theta = \cos ^{2}\theta - \sin ^{2}\theta\]
OpenStudy (anonymous):
can you do steps further to get the answer please ?
OpenStudy (cwrw238):
also use sin 2O = 2 sin O cos O
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OpenStudy (anonymous):
yeah @cwrw238 plz help me
OpenStudy (cwrw238):
so we have cos^2 O - sin ^2 O + 6 sin O cos O - 2 = 0
OpenStudy (anonymous):
got it.. next ?
OpenStudy (cwrw238):
this is not as straight forward as i thought..
OpenStudy (anonymous):
yeah i know
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OpenStudy (cwrw238):
i thought we might get a quadratic equation which we could easily solve but we cant
OpenStudy (anonymous):
yeah it wont end in a quadratid
OpenStudy (cwrw238):
one way would be to replace cos^2 x by 1 - sin^2 x and cos x by
sqrt(1 - sin^ 2 x) which would be a bit messy....
OpenStudy (anonymous):
it will be too long i think
OpenStudy (anonymous):
@phi what do you think? could you help ?
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OpenStudy (anonymous):
well you can do this problem by another way
OpenStudy (anonymous):
please help
OpenStudy (anonymous):
consider a triangle with base of 3 units and height of 1 units
OpenStudy (anonymous):
the triangle will be a right angled triangle
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
now the hypotenuse will be \[\sqrt{10}\]
OpenStudy (anonymous):
and the angle 71.6
OpenStudy (anonymous):
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