Question

Help with application of ellipses and hyperbolas

Answer 1

\[\frac{ x^2 }{ 36 }-\frac{ (y+6)^2 }{ 12 }=1\]

Answer 2

-6+/-sqrt12/6(x-0)

Answer 3

@freckles does this look right?

Answer 4

yep this looks right
\[y=-6 \pm \frac{\sqrt{12}}{6}x\]
this feels like almost the same question :p

Answer 5

Indeedly but i believe they want sqrt3 /3

Answer 6

\[\sqrt{12}=\sqrt{4 \cdot 3} =\sqrt{4} \cdot \sqrt{3}\]

Answer 7

sqrt 4 is 2

Answer 8

so 2 sqrt 3 / 6