Question

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(1-cosΘ)(1+cosΘ)/(1-sinΘ)(1+sinΘ)?

Answer 1

Possible Answers:
sin2 Θ
cos2 Θ
tan2 Θ
cosine theta over sine theta

Answer 2

foil o^_^o
denominator and numerator

Answer 3

How do I do that?

Answer 4

\[
\frac{(1-\cos(\theta))(1+\cos(\theta))}{(1-\sin(\theta))(1+\sin(\theta))}=\frac{1-\cos^2(\theta)}{1-\sin^2(\theta)}
\]

Answer 5

bec one parentheses is negative and one is positive
so square of first term and square of 2nd term
middle terms would cancel out