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Mathematics 13 Online
OpenStudy (drewbooks):

Which linear expression is a factor of this polynomial function? f(x) = x^3 + 3x^2 – x – 3

OpenStudy (drewbooks):

A) x-1 B) x+1 C) x+3 D) x-3

OpenStudy (anonymous):

f(1) =?

OpenStudy (anonymous):

replace 1 into f

OpenStudy (anonymous):

knock knock, last attempt: f(1) =?

OpenStudy (drewbooks):

I don't see what I'm supposed to do with that.

OpenStudy (anonymous):

just answer me, you can see after then.

OpenStudy (drewbooks):

f(1) = 1^3 + 3(1^2) – 1 – 3?

OpenStudy (anonymous):

yup, =?

OpenStudy (drewbooks):

0?

OpenStudy (anonymous):

Bingo,

OpenStudy (anonymous):

f(1) =0, that shows 1 is a root of the expression. In other words, (x-1) is a factor or f(x) . Done

OpenStudy (drewbooks):

Ah, alright. Why is it x-1 rather than x+1?

OpenStudy (anonymous):

If you take x+1, that is the root is -1, not 1, \(f(-1) = (-1)^3 +3(-1)^2 -1-3= -2\neq 0\)

OpenStudy (drewbooks):

Got it. Thank you very much. :-)

OpenStudy (anonymous):

hehehehe.. sometimes, be patient to get a good trick is ok, right?

OpenStudy (drewbooks):

Indeed! At first, I thought I was just misunderstanding what you wanted me to do.

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