Question

factor
3r^2-16r-7=5

Answer 1

first you want it to be in this form: ax + bx + c = 0

Answer 2

ok

Answer 3

ax^2+bx+c my bad

Answer 4

So what can you do to have it in that form? Can you try?

Answer 5

3r^2-16r-12=0

Answer 6

ok perfect

Answer 7

same process as before... multiply a and c

then find the factors that add to - 16

Answer 8

-18 and 2

Answer 9

r the factors

Answer 10

that's correct... so start with

\[\frac{(3r - 18)(3r + 2)}{3}\]

factor the 1st linear factor... you will then see a common factor that cancels with the denominator...

what is left is the 2 linear factors

Answer 11

common factor is 3

Answer 12

great so it becomes

\[\frac{3(x - 6)(3x + 2)}{3} = (x -6)(3x + 2) \]

now you can solve the linear factors if necessary

Answer 13

this method avoids the messy cross method stuff..

Answer 14

ok so i got x=6 and x=2/3

Answer 15

is that right

Answer 16

the 2nd choice should be x = -2/3

Answer 17

oh

Answer 18

x = 6 is correct

Answer 19

k thanks

Answer 20

remember you are solving

x - 6 = 0 and 3x + 2 = 0

Answer 21

oh yea

Answer 22

can u help me with another question plz