what is the fifth term of the expansion of (a-3b)^5
choices are a)405ab^4 b)405ab^5 c)81ab^4 d/-405ab^4
Are you using binomial theorem?
yes
Ok, cool. So, we need to identify the x, y, and r in the formula.
?
Does your binomial theorem look like this: http://www.mathwarehouse.com/algebra/polynomial/binomial-theorem.php Look about halfway down the page
similar
Does yours use different letters?
so far i got 5C4a^0b^4
yes
Hm, I see how you got b^4, but I don't get a^0
since its the fifth term wouldn't the exponent be 0
or 1. i dont know
I get the fifth term to have x^(r-4) which would make a^(5-4)
Yep, which is a^1
so what would be the answer
Ok, I see how you would get what you put before, but I would make another slight adjustment. 5C4a^1(3b)^4
Does that form make sense?
ok
do u know what 5c4 is
Yes, that is a combination. Most calculators have a combination button.
Oh, and I made a slight error. It should be 5C4a^1(-3b)^4
Do you see a button on your calculator that looks like nCr?
If not, you can use this formula:|dw:1431977689302:dw|
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